Integrand size = 20, antiderivative size = 44 \[ \int \frac {1}{x \sqrt {a+b x^2+c x^4}} \, dx=-\frac {\text {arctanh}\left (\frac {2 a+b x^2}{2 \sqrt {a} \sqrt {a+b x^2+c x^4}}\right )}{2 \sqrt {a}} \]
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Time = 0.02 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {1128, 738, 212} \[ \int \frac {1}{x \sqrt {a+b x^2+c x^4}} \, dx=-\frac {\text {arctanh}\left (\frac {2 a+b x^2}{2 \sqrt {a} \sqrt {a+b x^2+c x^4}}\right )}{2 \sqrt {a}} \]
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Rule 212
Rule 738
Rule 1128
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x+c x^2}} \, dx,x,x^2\right ) \\ & = -\text {Subst}\left (\int \frac {1}{4 a-x^2} \, dx,x,\frac {2 a+b x^2}{\sqrt {a+b x^2+c x^4}}\right ) \\ & = -\frac {\tanh ^{-1}\left (\frac {2 a+b x^2}{2 \sqrt {a} \sqrt {a+b x^2+c x^4}}\right )}{2 \sqrt {a}} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.93 \[ \int \frac {1}{x \sqrt {a+b x^2+c x^4}} \, dx=\frac {\text {arctanh}\left (\frac {\sqrt {c} x^2-\sqrt {a+b x^2+c x^4}}{\sqrt {a}}\right )}{\sqrt {a}} \]
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Time = 0.05 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.89
method | result | size |
default | \(-\frac {\ln \left (\frac {2 a +b \,x^{2}+2 \sqrt {a}\, \sqrt {c \,x^{4}+b \,x^{2}+a}}{x^{2}}\right )}{2 \sqrt {a}}\) | \(39\) |
elliptic | \(-\frac {\ln \left (\frac {2 a +b \,x^{2}+2 \sqrt {a}\, \sqrt {c \,x^{4}+b \,x^{2}+a}}{x^{2}}\right )}{2 \sqrt {a}}\) | \(39\) |
pseudoelliptic | \(-\frac {\ln \left (\frac {2 a +b \,x^{2}+2 \sqrt {a}\, \sqrt {c \,x^{4}+b \,x^{2}+a}}{x^{2}}\right )}{2 \sqrt {a}}\) | \(39\) |
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Time = 0.29 (sec) , antiderivative size = 124, normalized size of antiderivative = 2.82 \[ \int \frac {1}{x \sqrt {a+b x^2+c x^4}} \, dx=\left [\frac {\log \left (-\frac {{\left (b^{2} + 4 \, a c\right )} x^{4} + 8 \, a b x^{2} - 4 \, \sqrt {c x^{4} + b x^{2} + a} {\left (b x^{2} + 2 \, a\right )} \sqrt {a} + 8 \, a^{2}}{x^{4}}\right )}{4 \, \sqrt {a}}, \frac {\sqrt {-a} \arctan \left (\frac {\sqrt {c x^{4} + b x^{2} + a} {\left (b x^{2} + 2 \, a\right )} \sqrt {-a}}{2 \, {\left (a c x^{4} + a b x^{2} + a^{2}\right )}}\right )}{2 \, a}\right ] \]
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\[ \int \frac {1}{x \sqrt {a+b x^2+c x^4}} \, dx=\int \frac {1}{x \sqrt {a + b x^{2} + c x^{4}}}\, dx \]
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Exception generated. \[ \int \frac {1}{x \sqrt {a+b x^2+c x^4}} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.29 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.86 \[ \int \frac {1}{x \sqrt {a+b x^2+c x^4}} \, dx=\frac {\arctan \left (-\frac {\sqrt {c} x^{2} - \sqrt {c x^{4} + b x^{2} + a}}{\sqrt {-a}}\right )}{\sqrt {-a}} \]
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Time = 13.29 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x \sqrt {a+b x^2+c x^4}} \, dx=-\frac {\ln \left (\frac {1}{x^2}\right )}{2\,\sqrt {a}}-\frac {\ln \left (2\,a+2\,\sqrt {a}\,\sqrt {c\,x^4+b\,x^2+a}+b\,x^2\right )}{2\,\sqrt {a}} \]
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